Quote Originally Posted by doctorxring
Hi rnvinc

I have a problem on 360 imaging as well as side scan, as they both
work the same. I have not been able to resolve it and I thought I
would ask for your opinion as you are well versed in side imaging.
I'm including a scan for an example.

Let's assume that the boat is pinned with two power poles so it
is fixed and cannot move. The bottom is level.

Question 1 -- Would the spot marked A in this scan image be directly
under the side scan transducer ?

Question 2 -- The range on this screen shot is set to 30 feet. The depth is 4.4 feet.
Is the distance from a point on the bottom directly under the transducer (A) to a point on the bottom
at the extreme edge of the scan (B) 25.6 feet ?

thanks kindly, Chris

Hey Chris ... You have the basic idea correct for Question 1 ...

The intersection point between the dark water column and where the bottom detail starts is, indeed directly under the boat and equal to water depth ... So any target that is closer to the 360 xducer than the "value of the water depth" will be displayed in the dark water column (just like in SI - targets closer to the SI xducer than the "value of the water depth" will be displayed in the dark water column) ...

Question 2 is easily misinterpreted to think that the water depth subtracted from the Range equals bottom coverage - which is incorrect ...

The Range value entered is the "slant line distance" from the xducer to the point - so bottom coverage can be calculated using the Phythagorean theory as below ...



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