Formula for current is I=e/r where I is the Current, e is the voltage, and r is the resistance. To make things simple lets say that you have a 12 volt circuit and a load of 12 ohms. The total current draw for this circuit will be 1 amp. If the resistance should increase for whatever reason lets say to a resistance of 120 ohms on this same circuit. To determine the current (I) you will neet to divide E(the voltage, in this case 12) by the resistance( in this case an INCREASE to 120 ohms) and you will have a current of .1amps or 100ma. However if you decrease the the resistance. Lets say to 1 ohm for ease in calculating, you will have the voltage =12 divided by 1 ohm, the total current will be 12 amps for this circuit.

Increasing the resistance (loose connections) always decreases the current and will NEVER cause a fuse to blow. However, a loose connection will generate heat which will sometime melt the insulation on the conductors and cause a shorted condition, which is a decrease in the amount of resistance and will cause a fuse to blow.

I didn't make the law. Mr Ohm did.

Nothing personal, it's just the way things are. Don't take my word for this. Ask the most knowledgable person on the board if ohms law works. This is what I do for a living. I'd rather be showing fish pics than talking electricty.

I am 100% in agreement with your statement "loose connections cause trouble" and I also know that Zettler doesn't need to understand ohms law to be able to get all his stuff running right.